Question

Find the number of points of extremum of f(x) = |x² – 1| + |x³ – 1| + |x⁵ – 1|

Answer 1

We have f(x) = |x² – 1| + |x³ – 1| + |x⁵ – 1|

Clearly, the number of points of extremum is 3 at x = 1/2, 0, 1