Question

∫e^{tan^-1x}((1 + x + x²)/(1 + x²))dx  is equal to

(A) xe^{tan^-1x} + c

(B) x²e^{tan^-1x} + c

(C) 1/(xe^{tan^-1x}) + c

(D) (1/x²)e^{tan^-1x} + c

Answer 1

Answer is (A) xe^{tan^-1x} + c