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+2 votes
3.3k views
in Integrals calculus by (41.7k points)

Value of the integral ∫ex[(1 + (1 - x2)sin-1x)/(1 - x2)]dx  is equal to

(A) exsin-1x + c

(B) ex/√(1 - x2) + c

(C) ex√(1 - x2) + c

(D) √(1 - x2)sin-1x + c

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