

Resolving vector B into two rectangular components we have B cosθ along OC and B sinθ along OD.The resultant vector is along OC.
R = B cosθ [A.T.Q.]
R = B/2 = B cosθ
or, cosθ = 1/2 or, θ = 60°
Hence angle between vector A and B
= ∠AOB = 90° + 60° = 150°.