Question

The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of 1.0 m. If the piston moves with S.H.M. with an angular frequency of 200 rev/min, what is its maximum seed?

Answer 1

Here, amplitude,

r = 1/2 m

Angular velocity, ω = 200 rev/min. = 200/60 rev/sec.

Maximum speed, v_max = ωr = 1/2 x 200/60

= 1.667 ms^-1 = 1.667 x 60 = 100 m min^-1