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+1 vote
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in Physics by (62.4k points)

Find the dimension of B2/2μ0

(1) ML-1T-2

(2) ML2T-2

(3) ML-1T2

(4) ML-2T-1

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1 Answer

+1 vote
by (64.8k points)

Answer is (1)

Energy density in magnetic field = B2/2μ0

= {Force x displacement}/{(displacement)3}

= {MLT-2.L}/{L3} = ML-1T-2

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