Question

If speed V, area A and force F are chosen as fundamental units, then the dimension of Young’s modulus will be

(1) FA^–1V⁰ 

(2) FA²V^–1 

(3) FA²V^–2 

(4) FA²V^–3

Answer 1

Answer is (1) FA^–1V⁰

∵ [Young’s modulus] = \(\Big[\frac{Force}{Area}\Big]\)

⇒ [Young’s modulus] = FA^–1

⇒ [Young’s modulus] = FA^–1V⁰