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+1 vote
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in Physics by (48.3k points)

The value of the acceleration due to gravity is g1 at a height h =\(\frac{R}{2}\) (R = radius of the earth) from the surface of the earth. It is again equal to g1 at a depth d below the surface of the earth. The ratio d (\(\frac{d}{R}\)) equals

(1) \(\frac{5}{9}\)

(2) \(\frac{1}{3}\)

(3) \(\frac{7}{9}\)

(4) \(\frac{4}{9}\)

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