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Position of a particle as a function of time is given as x^2 = at^2 + 2bt + c, where a, b, c are constants.

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Position of a particle as a function of time is given as x2 = at2 + 2bt + c, where a, b, c are constants. Acceleration of particle varies with x–n then value of n is. 

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1 Answer

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by (52.8k points)

2 = at2 + 2bt + c

2xv = 2at + 2b

xv = at + b

v2 + ax = a

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