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+2 votes
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in Mathematics by (36.6k points)

Minimize = 20x + 10y

subjected to x + 2y ≤ 40, 3x + y ≥ 30, 4x + 3y ≥ 60

x ≥ 0, y ≥ 0

1 Answer

+2 votes
by (33.2k points) 1 flag
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Best answer

First we draw the lines

x + 2y = 40, 3x + y = 30, 4x + 3y = 60

The feasible region(shaded region) is the bounded region "EAQPA''

The vertices of the region are 

E(15,0), A(40,0), Q(4,18) and P(6,12) 

Given objective function is 

z = 20x + 10y

At, E(15,0), z = 300

At, A(40,0), z = 800

At, Q(4,18), z = 260

At, P(6,12), z = 240

Hence, Zmin = 240 at x = 6, y = 12

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