First we draw the lines
x + 2y = 40, 3x + y = 30, 4x + 3y = 60

The feasible region(shaded region) is the bounded region "EAQPA''
The vertices of the region are
E(15,0), A(40,0), Q(4,18) and P(6,12)
Given objective function is
z = 20x + 10y
At, E(15,0), z = 300
At, A(40,0), z = 800
At, Q(4,18), z = 260
At, P(6,12), z = 240
Hence, Zmin = 240 at x = 6, y = 12