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If a, b, c are GP. Prove that log^na log^n6 log^nc are in HP.

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If a, b, c are GP. Prove that logna logn6 lognc are in HP.

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Given, a, b, c are in GP = b2 = ac 

Taking log on both sides 

2 log 6 = log a + log c 

⇒ loga n logb n logc n are inn AP 

⇒ loga n logb n logc n are in HP.

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