Question

Which term of A.P 4 is (5(1/3) - 4), 6(2/3) .... is 104? 

Answer 1

In given A.P: a = 4, d = 5^1/3 – 4 = 16/3 – 4 = 4/3

Let n^th term be 104 = T_n = a + (n – 1)d 

⇒ 4 + (n – 1)^4/3 = 104 

⇒ 12 + 4n – 4 = 312 ⇒ 4n – 4 = 312 

⇒ 4n = 312 – 8 

⇒ 4n = 304 

∴ n = 76