Find the oxidation state of sulphur in the following compounds?

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SurajKumar · Answer 1 · 2020-02-14T21:42:09+0000

S₂O₄^2-, S₂O₈^2-

In H₂S, +2 +x = 0; x = -2

In H₂SO₄, +2 +x - 8 = 0; x = +6

In S₂O₄^2-, 2x - 8 = -2; 2x = 6, x = +

In S₂O₄^2-, let one of S = x, than 2x + 4(-8) = -2 ∴ x = +3

In S₂O₈^2- there is peroxide linkage, therefore oxidation state of 'S' is 6 because