Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
588 views
in Determinants by (53.2k points)

Prove that \(\begin{vmatrix} a^2& bc & ac + c^2 \\[0.3em] a^2 + ab & b^2 &ac\\[0.3em] ab &b^2 + bc & c^2 \end{vmatrix}\) = 4a2b2c2

1 Answer

+1 vote
by (58.5k points)
selected by
 
Best answer

expand along c1

= 2ab2c{1 x (a - c)c + c(a + c)}

= 2ab2c{ac - c2 + ac + c2} = 2ab2c x 2ac

= 4a2b2c2.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...