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in Determinants by (52.1k points)

\(\begin{vmatrix} 1 & a & bc \\[0.3em] 1 &b & ca \\[0.3em] 1& c&ab \end{vmatrix}\) = \(\begin{vmatrix} 1 & a & a^2 \\[0.3em] 1 &b & b^2 \\[0.3em] 1& c&c^2 \end{vmatrix}\)

1 Answer

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Best answer

On applying row operation R2 → a R1, R2 → b R2 - Rand R3→ c R3 - R3

Hence proved

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