Question

Evaluate: Δ = \(\begin{vmatrix} 0&sin α& -cosα \\[0.3em]-sinα & 0 & sinβ \\ cosα & -sinβ & 0\end{vmatrix}\)

Answer 1

⇒ |A| = 0 (0 – sinβ (–sinβ)) –sinα (–sinα × 0 – sinβ cosα) – cosα ((–sinα) (–sinβ) – 0 × cosα)

|A| = 0 + sinα sinβ cosα – cosα sinα sinβ

|A| = 0