Question

At what temperature 128 g of SO₂ confined in vessel of 5 dm³ capacity will exhibit a pressure of 10.0 bar? Given a = 6.7 bar L² mol^-2 and b= 0.0564 L mol^-1 

Answer 1

w = 128 g

 V = 5 dm³ 

P = 10.0 bar 

M_SO2 = 64 g 

n = w/M = 128/64 = 2 

 Putting values in equation : ( P + an² /V² ) (V – nb) = nRT 

We get T = 329 K