Given,
Radius of the cylindrical portion (R) = 20 m
Height of the cylindrical portion (h1) = 4.2 m
Height of the conical portion (h2) = 2.1 m
Now, we know that
Volume of the Cylindrical portion (V1) = πr2 h1
V1 = π(20)24.2
V1 = 5280 m3
And, the volume of the conical part (V2) = 1/3 × 22/7 × r2 × h2
V2 = 13 × 22/7 × 202 × 2.1
V2 = 880 m3
Thus, the total volume of the tent (V) = volume of the conical portion + volume of the Cylindrical portion
V = V1 + V2
V = 6160 m3
Therefore, volume of the tent is 6160 m3 .