
Given,
Base diameter of the cylindrical base of the petrol tank = 21 cm
So, its radius (r) = diameter/2 = 21/2 = 10.5 cm
Height of the Cylindrical portion of the tank (h1) = 18 cm
Height of the Conical portion of the tank (h2) = 9 cm
Now, we know that
The volume of the Cylindrical portion (V1) = πr2 h1
V1 = π(10.5)2 18
V1 = 6237 cm3
The volume of the Conical portion (V2) = 1/3 × 22/7 × r2 × h2
V2 = 1/3 × 22/7 × 10.52 × 9
V2 = 1039.5 cm3
Therefore, the total volume of the tank (V) = 2 x volume of a conical portion + volume of the Cylindrical portion
V = V1 + V2 = 2 x 1039.5 + 6237
V = 8316 cm3
So, the capacity of the tank = V = 8316 cm3 .