(3a-2)/3 + (2a+3)/2 = a + 7/6
Let us rearrange the equation
(3a-2)/3 + (2a+3)/2 – a = 7/6
By taking LCM for 2 and 3 which is 6
((3a-2)2 + (2a+3)3 – 6a)/6 = 7/6
(6a – 4 + 6a + 9 – 6a)/6 = 7/6
(6a + 5)/6 = 7/6
6a + 5 = 7
6a = 7-5
6a = 2
a = 2/6
a = 1/3
Let us verify the given equation now,
(3a-2)/3 + (2a+3)/2 = a + 7/6
By substituting the value of ‘a’ we get,
(3(1/3)-2)/3 + (2(1/3) + 3)/2 = 1/3 + 7/6
(1-2)/3 + (2/3 + 3)/2 = (2+7)/6
-1/3 + (11/3)/2 = 9/6
-1/3 + 11/6 = 3/2
(-2+11)/6 = 3/2
9/6 = 3/2
3/2 = 3/2
Hence, the given equation is verified.