x – (x-1)/2 = 1 – (x-2)/3
Let us rearrange the equation
x – (x-1)/2 + (x-2)/3 = 1
By taking LCM for 2 and 3 which is 6
(6x – (x-1)3 + (x-2)2)/6 = 1
(6x – 3x + 3 + 2x – 4)/6 = 1
(5x – 1)/6 = 1
By cross-multiplying
5x – 1 = 6
5x = 6 + 1
x = 7/5
Let us verify the given equation now,
x – (x-1)/2 = 1 – (x-2)/3
By substituting the value of ‘x’ we get,
7/5 – (7/5 – 1)/2 = 1 – (7/5 – 2)/3
7/5 – (2/5)/2 = 1 – (-3/5)/3
7/5 – 2/10 = 1 + 3/15
(14 – 2)/10 = (15+3)/15
12/10 = 18/15
6/5 = 6/5
Hence, the given equation is verified.