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in Gauss’s Law and its Applications by (61.2k points)

In a closed surface, the electric flux entering and leaving out the surface are 400 Nm2/C and 800 Nm2/C respectively. What would be the charge enclosed by the surface?

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The electric flux entering in surface
ϕ1 = -400Nm2/C
Electric flux leaving out through surface
ϕ2 = 800Nm2/C
∴ Total flux linked with the closed surface
ϕ = ϕ1 + ϕ2 = -400 + 800 = 400Nm2/C
From Gauss’s theorem,
ϕE = \(\frac{1}{\varepsilon_{0}}\) Σq
Σq = ϕE × ε0
= 400 × 8.86 × 10-12
= 3.54 × 10-9 C
= 3.54 nC

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