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in Gauss’s Law and its Applications by (61.2k points)

A uniformly charged sphere of diameter 2.4 m has surface charge density of 80 pC/m2. Determine the total electric flux leaving out the spherical surface along with the spherical charge.

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(a) Surface charge density on the surface of uniformly charged sphere
σ = \(\frac{q}{A}=\frac{q}{4 \pi r^{2}}\)
q = 4πr2σ
= 4 × 3.14 × 1.2 × 1.2 × 80.0 × 10-6 C
= 1447 × 10-6 C
= 1.447 × 10-3 C
= 1.45 × 10-3 C = 1.45 mC

b) From Gauss’s law if we consider surface of sphere as Gausssian surface then total charge on sphere will be bound to sphere.
∴ Leaving out flux through surface

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