Question

In a given figure, the potential difference across 4.5 μF capacitor in the circuit is:

(a) \(\frac{8}{3} \mathrm{V}\)
(b) 4 V
(c) 6 V
(d) 8 V

Answer 1

(d) 8 V
Adding 6 μF and 3 μF in parallel
C₁ = 6 μF + 3 μF = 9μF
Adding C₁ and 4.5 μF in series