Question

The potential energy between plates of a charged parallel plate capacitor is UQ. If a dielectric plate of dielectric constant er is placed between The gap of plates, then the new potential energy will be :
(a) \(\frac{U_{0}}{\varepsilon_{r}}\)
(b) U₀ε_r²
(c) \(\frac{U_{0}}{\varepsilon_{r}^{2}}\)
(d) U₀

Answer 1

(a) \(\frac{U_{0}}{\varepsilon_{r}}\)
Energy decreases to ε_r times
U = \(\frac{U_{0}}{\varepsilon_{r}}\)