Question

What will be the effect on the potential between the plates of a charged parallel plate capacitor when both plates are carry nearest to each other. While the charge is constant. Explain?

Answer 1

q = CV
⇒ V = \(\frac{q}{C}\)
or, V ∝ \(\frac{1}{C}\) (when charge is constant)
On bringing them near d decreases but according to C = \(\frac{\varepsilon_{0} A}{d}\), C increases. Due to which potential d difference between plates decreases.