What is the value of molar conductivity ?

Question

Resistance of 0.2 M solution of an electrolyte is 50 ohm the specific conductance of the solution is 1.3 s m - 1.If the resistance of the 0.4 M solution of the same electrolyte is 260 ohm, its molar conductivity is?

Answer 1

The correct answer is 6.25 x 10^-4 S m² mol^-1

We have

\(\kappa=\frac{1}{R}\). Cell Constant

For 0.2 M solution:

1.3Sm^-1 = 1/50. Cell Constant

Cell constant = (1.3 x 50)

= 65m^-1

For 0.4 M solution:

\(\kappa= \frac{1}{260}\times65\)

= 0.25Sm^-1

Now,

\(Λ_m=\frac{\kappa}{Molarity}\)

= 0.25Sm^-1/0.4mL^-1

= 0.625 S m² mol^-1

= 6.25 x 10^-4 S m² mol^-1

Alternative Method

Comments

Wrong answer.....

---

No its a final answer

---

Answer is 6.25 * 10^-4

---

Yes, If you calculate the last term with respect to the power of 10 .but here no option is given so direct we use numerical value.

---

Can you please explain me how is that last line coming from I mean the correct answer.... It's so confusing

---

Thanks sir NYC

---

plz see above

---

Yes both are right sir thanks

---

OK... Thank you so much sir