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D and E are points on the sides AB and AC respectively of a ∆ABC such that DE || BC. Find the value of x, when AD = x cm, DB = (x – 2) cm, AE = (x + 2) cm and EC = (x – 1) cm.

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From figure, D and E are the points on the sides AB and AC respectively and DE || BC

then AD/DB = AE/EC

AD = x cm, DB = (x – 2) cm, AE = (x + 2) cm and EC = (x – 1) cm.

x/(x-2) = (x+2)/(x-1)

x(x-1) = (x+2)(x-2)

Solving above equation, we get

x = 4 cm

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