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25.3k views
in Trigonometry by (44.3k points)

Evaluate:

(5cos260° + 4sec230° - tan245°)/(sin230° + cos230°)

1 Answer

+1 vote
by (58.8k points)
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Best answer

We know that,

cos 30° = √3/2 ⇨ cos2 30° = 3/4

cos 60° = 1/2 ⇨ cos2 60° = 1/4

sec 30° =(2/√3) ⇨ sec2 30° = 4/3

tan 45° = 1 ⇨ tan2 45° = 1

sin 30° = 1/2 ⇨ sin2 30° = 1/4

Now,

(5cos260°+4sec230°-tan245°)/(sin230°+cos230°)

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