Question

The base of a right-angled triangle measures 48 cm and its hypotenuse measures 50 cm. Find the area of the triangle.

Answer 1

It is given that

Base = BC = 48 cm

Hypotenuse = AC = 50 cm

Consider AB = x cm

Using the Pythagoras theorem

AC² = AB² + BC²

By substituting the values

50² = x² + 48²

On further calculation

x² = 50² – 48²

So we get

x² = 2500 – 2304

By subtraction

x² = 196

By taking the square root

x = √196

So we get

x = 14cm

We know that the area of a right angled triangle = ½ × b × h

By substituting the values

Area of a right angled triangle = ½ × 48 × 14

On further calculation

Area of a right angled triangle = 24 × 14

By multiplication

Area of the triangle = 336 cm²

Therefore, the area of the triangle = 336 cm².

Answer 2

Hey

Case of right angled triangle :-

base = 48cm
hypotenuse= 50cm .

By Pythagoras theorem , we get

So ,

So ,

Perpendicular = 14 cm .

Now area of triangle = 1 / 2 * b * p
= 1 / 2 * 48 * 14
= 48 * 7
= 336 cm²

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