It is given that
Base = BC = 48 cm
Hypotenuse = AC = 50 cm
Consider AB = x cm
Using the Pythagoras theorem
AC2 = AB2 + BC2
By substituting the values
502 = x2 + 482
On further calculation
x2 = 502 – 482
So we get
x2 = 2500 – 2304
By subtraction
x2 = 196
By taking the square root
x = √196
So we get
x = 14cm
We know that the area of a right angled triangle = ½ × b × h
By substituting the values
Area of a right angled triangle = ½ × 48 × 14
On further calculation
Area of a right angled triangle = 24 × 14
By multiplication
Area of the triangle = 336 cm2
Therefore, the area of the triangle = 336 cm2.