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The number of distinct prime factors of the largest 4-digit number is

(A) 2 (B) 3 (C) 5 (D) 11

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(B) 3

The largest 4 – digit number = 9999

Prime factors of 9999 = 3 × 3 × 11 × 101

So, 9999 = 32 × 11 × 101

Therefore, distinct prime factors are = 3, 11 and 101

Number of distinct prime factors of the largest 4-digit number is = 3

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