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The number of distinct prime factors of the smallest 5-digit number is (A) 2 (B) 4 (C) 6 (D) 8

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The number of distinct prime factors of the smallest 5-digit number is

(A) 2 (B) 4 (C) 6 (D) 8

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1 Answer

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(A) 2

The smallest 5 – digit number = 10000

Prime factors of 10000 = 2 × 2 × 2 × 2 × 5 × 5 × 5 × 5

So, 10000 = 24 × 54

Therefore, distinct prime factors are = 2 and 5

Number of distinct prime factors of the smallest 5-digit number is = 2

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