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Construct a ∆ABC where a = 6.5 cm, b = 7.2 cm, c = 8 cm. Draw the bisector of ∠B which meets AC at the point M.

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Steps of construction:

1. Draw AC = 7.2 cm.

2. By taking A as centre, draw an arc of radius 8 cm.

3. Again take C as centre and draw an arc of radius 6.5 cm which cuts the previous arc at B.

4. Join AB and AC. 

This gives the required ∆ABC.

5. Now draw BM as bisector of ∠B which meets AC at M.

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