Question

Construct a ∆ABC where AB = AC = 8 cm, ∠A = 15°. Draw a bisector of ∠B which meets the opposite side.

Answer 1

Steps of construction:

1. Draw AB = 8 cm as base.
2. At A draw an angle of 75°.
3. Now taking A as centre, draw an arc of radius 8 cm which cuts the arm of the angle 75° at C. Join C to B.
4. Now draw angle bisector of ∠B which meets the opposite side AC at E (suppose).

Hence, ∆ABC is the required triangle