Question

In figure, D divides the side BC of ∆ABC in the ratio 3 : 5. Show that ar (∆ABD) = 3/8ar (∆ABC)

Answer 1

We are given that D divides BC in the ratio 3 : 5

i.e. BD : CD = 3 : 5

⇒ BD = \(\frac { 3 }{ 8 }\) DC …(i)

Draw AE ⊥ BC