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The perimeter of a right-angled triangle is 60 cm. Its hypotenuse is 26 cm. Find the area of the triangle.

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Let base and height of a right angled triangle be b and h cm respectively

b + h + 26 = 60

⇒ b + h = 34

⇒ (b + h)2 = (34)2

Also b2 + h2 = (26)2 …(ii)

Subtracting (ii) from (i), we get

(b + h)2 – (b2 + h2) = (34)2 – (26)2

⇒ b2 + h2 + 2bh – b2 – h2 = (34 – 26)(34 + 26)

⇒ 2bh = 8 x 60

⇒ bh = 240

⇒ Area = \(\frac { 1 }{ 2 }\) x b x h 

\(\frac { 1 }{ 2 }\) x 240 = 120

Hence, area =120 cm2

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