To find r,
Lets consider the given expression,
8Cr – 7C3 = 7C2
8Cr = 7C2 + 7C3
As we know that nCr + nCr + 1 = n + 1Cr + 1
8Cr = 7 + 1C2 + 1
8Cr = 8C3
Then, we know that if nCp = nCq, now one of the following conditions need to be satisfied:
(i) p = q
(ii) n = p + q
Therefore from the question 8Cr = 8C3, we can say that
Lets check for condition (i)
r = 3
Lets also check for condition (ii)
8 = 3 + r
r = 5
Hence, the values of ‘r’ are 3 and 5.