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If 8Cr – 7C3 = 7C2, find r.

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To find r, 

Lets consider the given expression,

8Cr – 7C3 = 7C2

8Cr = 7C2 + 7C3

As we know that nCr + nCr + 1 = n + 1Cr + 1

8Cr = 7 + 1C2 + 1

8Cr = 8C3

Then, we know that if nCp = nCq, now one of the following conditions need to be satisfied:

(i) p = q

(ii) n = p + q

Therefore from the question 8Cr = 8C3, we can say that

Lets check for condition (i)

r = 3

Lets also check for condition (ii)

8 = 3 + r

r = 5

Hence, the values of ‘r’ are 3 and 5.

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