Question

AmatrixP[15] [10] is stored with each element requiring 8 bytes of storage. If the base address at P[0] [0] is 1400, determine the address at P[10] [7] when the matrix is stored in Row Major Wise.

Answer 1

Row Major Address Formula: M[i] [j] = B(A) + W[(i – Ir)*column + (j – Ic)] 

In the given problem, Address of P[10][[7] is asked. 

1400 is base address, column =10, W = 8 bytes, i = 10, j = 7, Ir = 0 and Ic = 0. 

Address of P[10] [7]: 

= 1400 + 8[(10 – 0)*10 + (7 – 0)] 

= 1400 + 8[100 + 7] 

= 1400 + 8*107 

= 2256