Let ABCD is a rectangle where AB = 4.5 cm and AC = 5.5 cm
In right angled triangle ∆ABC, ∠B = 90°.
∴ From Pythagorous Theorem
BC2 = AC2 – AB2 = 5.52 – 4.52
= (5.5 + 4.5) (5.5 – 4.5) = 10 x 1
BC2 = 10
BC= 3.16 m
∴ Perimeter of rectangle = 2(AB + BC)
= 2(4.5 + 3.16) cm
= 2 x 7.66
= 15.32 cm