![](https://www.sarthaks.com/?qa=blob&qa_blobid=15995442320805757917)
Steps of construction:
1. Draw a line segment PQ = 4.
2. Draw an arc of radius 4 cm from point P.
3. Draw another arc of radius 3.5 cm which intersects prior arc at point R.
4. Join PR and QR.
Thus ∆PQR is required triangle.
also ∵ PQ = QR = 4 cm.
∴ Thus ∆PQR is an isosceles triangle.