Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
735 views
in Construction of Triangles by (50.4k points)
closed by

Construct the right angled triangle ∆PQR, where ∠Q = 90°, QR = 8 cm and PR = 10 cm.

1 Answer

+1 vote
by (48.4k points)
selected by
 
Best answer

Steps of construction :

1. Draw QR = 8 cm.

2. Make ∠XQR = 90° at point Q.

3. Make an arc of 10 cm from point R which cuts QX at point P.

4. Join RP.

Thus ∆PQR is required triangle

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...