Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
9.1k views
in Pythagoras Theorem by (47.7k points)
closed by

In ∆PQR, point S is the midpoint of side QR. If PQ = 11, PR = 17, PS = 13, find QR.

1 Answer

+1 vote
by (47.0k points)
selected by
 
Best answer

In ∆PQR, point S is the midpoint of side QR. [Given] 

∴ seg PS is the median. 

∴ PQ2 + PR2 = 2 PS2 + 2 SR2 [Apollonius theorem]

∴ 112 + 172 = 2 (13)2 + 2 SR2 

∴ 121 + 289 = 2 (169)+ 2 SR2 

∴ 410 = 338+ 2 SR2 

∴ 2 SR2 = 410 – 338

∴ 2 SR2 = 72 

∴ SR2 = 72/2 = 36 

∴ SR = \(\sqrt {36}\) [Taking square root of both sides] 

= 6 units Now, QR = 2 SR [S is the midpoint of QR] 

= 2 × 6 

∴ QR = 12 units

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...