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If P(Z > z) = 0.5832 what is the value of z (z has a standard normal distribution)? 

(a) -0.48 

(b) 0.48 

(c) 1.04 

(d) -0.21

1 Answer

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Best answer

(d) -0.21

P(0 < Z < z) = 0.5832 – 0.5 = 0.0832 

From tables, z = 0.21 

Since z is to the left of Z = 0, the required value is -0.21

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