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What is the standard deviation of the number of recoveries among 48 patients, the probability of recovering is 0.75.

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What is the standard deviation of the number of recoveries among 48 patients, the probability of recovering is 0.75.

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Given n = 48, p = 0.75, q = 0.25 

This is a binomial distribution. 

The variance is given by Var (X) = npq 

= (48) (0.75) (0.25) 

= 9 . 

So the standard deviation is √9 = 3

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