Given,
AB = 6 cm, BC = 9 cm, CD = 12 cm and SP = 36 cm
Also,
PA, QB, RC and SD are all perpendiculars to line l.
∴ PA:QB:RS = AB:BC:CD
= 6:9:12
Let PQ = 6x, QR = 9x and RS = 12x
Since, length of PS = 36 km
∴ PQ + QR + RS = 36
⇒ 6x + 9x + 12x = 36
⇒ 27x = 36