Question

Which amount of chlorine gas liberated at anode, if 1 ampere current is passed for 30 minutes from NaCI solution? 

(a) 0.66 moles 

(b) 0.33 moles 

(c) 0.66 g 

(d) 0.33 g

Answer 1

(c) 0.66 g

2Cl^- → Cl₂ + 2e^- 

Q = It. 

Amount of current passed 

= 1 x 30 x 60 = 1800C 

The amount of Cl₂ liberated by passing 1800 coulomb of electric charge

= \(\frac{1\times1800\times71}{2\times96500}\)

= 0.66g