Question

If a current of 0.5 ampere flows through a metallic wire for 2 hours, then how many electrons would flow through the wire?

Answer 1

Q (coulomb) = 1 (ampere) x t(sec) 

= 0.5 ampere x 2 x 60 x 60 = 3600C 

A flow of IF, i.e., 96500 C is equivalent to the flow of 1 mole of electrons 

i.e., 6.023 x 10²³ electrons

3600 C is equivalent to flow of electrons

= \(\frac{6.02\times10^{23}}{96500}\) x 3600 2.246 x 10²² electrons,