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+1 vote
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in Physics by (48.3k points)
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 Activities of three radioactive substances A, B and C are represented by the curves A, B and C, in the figure. Then their half-lives  

T\(\frac{1}{2}\) (A) : T\(\frac{1}{2}\) (B) : T\(\frac{1}{2}\)(C) are in the ratio

(1) 2 : 1 : 3 

(2) 4 : 3 : 1 

(3) 2 : 1 : 1 

(4) 3 : 2 : 1

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1 Answer

+2 votes
by (48.7k points)

Correct answer is (1) 2 : 1 : 3

R =λN0eλt 

⇒ lnR = lnλN0 – λt  

⇒Slope of curves = –λ

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